Here's a full precedence expression evaluator following the recursive parsing
idea I linked-to in a comment on the OP's question.
To do this, first I wrote a simple BNF grammar for the expressions I wanted to process:
sum = product | sum "+" product | sum "-" product ;
product = term | product "*" term | product "/" term ;
term = "-" term | "(" sum ")" | number ;
This by itself requires a bit of experience to do simply and straightforwardly. If you have no experience with BNF you will find
it incredibly useful for describing complex streams of items like expressions, messages, programming langauges, ...
Using that grammar, I followed the procedure outlined in the other message
to produce the following code. It should be obvious that it is driven by grammar in a dumb mechanical way, and therefore pretty easy to write if you have that grammar.
(Untested. I'm not a JavaScript coder. This will surely contain a few syntax/semantic hiccups. Took me at about 15 minutes to code.)
var SE="Syntax Error";
function parse(str) { // returns integer expression result or SE
var text=str;
var scan=1;
return parse_sum();
function parse_sum() {
var number, number2;
if (number=parse_product()==SE) return SE;
while (true) {
skip_blanks();
if (match("+") {
number2=parse_product();
if (number2==SE) return SE;
number+=number2;
}
else if (match('-')) {
{ number2=parse_product();
if (number2==SE) return SE;
number-=number2;
}
else return number;
}
}
function parse_product() {
var number, number2;
if (number=parse_number()==SE) return SE;
while (true) {
if (match("*") {
number2=parse_term();
if (number2==SE) return SE;
number*=number2;
}
else if (match('/')) {
number2=parse_term();
if (number2==SE) return SE;
number/=number2;
}
else return number;
}
}
function parse_term() {
var number;
skip_blanks();
if (match("(")) {
number=parse_sum();
if (number=SE) return SE;
skip_blanks();
if (!match(")") return SE;
}
else if match("-") {
number= - parse_term();
}
else if (number=parse_number()==SE) return SE;
return number;
}
function skip_blanks() {
while (match(" ")) { };
return;
}
function parse_number() {
number=0;
if (is_digit()) {
while (is_digit()) {}
return number;
}
else return SE;
}
var number;
function is_digit() { // following 2 lines are likely wrong in detail but not intent
if (text[scan]>="0" && text[scan]<="9") {
number=number*10+text[scan].toInt();
return true;
}
else return false;
}
function match(c) {
if (text[scan]==c)
{ scan++; return true }
else return false;
}
}
It is straightforward to code such parsers/evaluators. See my SO answer on how to build a parser (which links to how to how to build an evaluator).
与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…