You can use Log10 to determine the correct break. Something like this could work:
double number = 4316000;
int mag = (int)(Math.Floor(Math.Log10(number))/3); // Truncates to 6, divides to 2
double divisor = Math.Pow(10, mag*3);
double shortNumber = number / divisor;
string suffix;
switch(mag)
{
case 0:
suffix = string.Empty;
break;
case 1:
suffix = "k";
break;
case 2:
suffix = "m";
break;
case 3:
suffix = "b";
break;
}
string result = shortNumber.ToString("N1") + suffix; // 4.3m
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