I need a SINGLE query that does this sequence in oracle.
select count(*) from table1
where request_time < timestamp'2012-05-19 12:00:00' and (end_time > timestamp'2012-05-19 12:00:00' or end_time=null);
select count(*) from table1
where request_time < timestamp'2012-05-19 13:00:00' and (end_time > timestamp'2012-05-19 13:00:00' or end_time=null);
select count(*) from table1
where request_time < timestamp'2012-05-19 14:00:00' and (end_time > timestamp'2012-05-19 14:00:00' or end_time=null);
select count(*) table1
where request_time < timestamp'2012-05-19 15:00:00' and (end_time > timestamp'2012-05-19 15:00:00' or end_time=null);
select count(*) from table1
where request_time < timestamp'2012-05-19 16:00:00' and (end_time > timestamp'2012-05-19 16:00:00' or end_time=null);
As you see the hour is increasing one by one.
here is the output
COUNT(*)
1085
COUNT(*)
1233
COUNT(*)
1407
COUNT(*)
1322
COUNT(*)
1237
I have written a query but it does not give me the right answer!
select col1, count(*) from
(select TO_CHAR(request_time, 'YYYY-MM-DD HH24') as col1 from table1
where request_time <= timestamp'2012-05-19 12:00:00' and (end_time >= timestamp'2012-05-19 12:00:00' or end_time=null))
group by col1 order by col1;
this query gives me a result set that sum of it's count(*) is equal to the first query written above!
here is the result:
COL1 COUNT(*)
------------- ----------------------
2012-05-19 07 22
2012-05-19 08 141
2012-05-19 09 322
2012-05-19 10 318
2012-05-19 11 282
See Question&Answers more detail:
os 与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…