Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
362 views
in Technique[技术] by (71.8m points)

php - jQuery voting system

So I am making a voting system, basically a Thumbs Up & Thumbs Down voting system. I am using CakePHP and jQuery with MySQL but want to make sure the front end is correct and this is the best way to do it.

I want the user to be able to change their vote, so utilizing jQuery is this the best and most efficient way? I'm fairly novice with jQuery when it comes to class manipulation.

the ID field is going to be the unique id of the photo the users will be voting on. This of course is just a test and this is not going to be the final product in production. There will be multiple photos on the page and the user votes Up or Down for each of them.

Here is the code.

<?php
echo $javascript->link('jquery/jquery-1.4.2.min',false);
?>
<script type="text/javascript">
    $(document).ready(function() {
        $('.vote').click(function () {
            if ($(this).hasClass("current")) {
                alert("You have already voted for this option!");

                return;
            }
            var parentId = $(this).parent("div").attr("id");
            if ($(this).hasClass("up")) {
                //Do backend query and checking here
                alert("Voted Up!");
                $(this).toggleClass("current");
                if ($("#" + parentId + "-down").hasClass("current")) {
                    $("#" + parentId + "-down").toggleClass("current");
                }
            }
            else if($(this).hasClass("down")) {
                //Do backend query and checking here
                alert("Voted Down!");
                $(this).toggleClass("current");
                if ($("#" + parentId + "-up").hasClass("current")) {
                    $("#" + parentId + "-up").toggleClass("current");
                }
            }



        });
    });
</script>
<div id="1234">
    <a id="1234-up" class="vote up" >+</a> | <a id="1234-down" class="vote down" >-</a>
</div>
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

You could do it this way:

<script type="text/javascript">
    $(document).ready(function() {
        $('.vote').click(function () {
            if ($(this).hasClass("current")) {
                alert("You have already voted for this option!");
            } else {
                var parentId = $(this).parent("div").attr("id");
                var error = false;

                if ($(this).hasClass("up")) {
                    //Do backend query and checking here (SET: error)
                    alert("Voted Up!");
                }
                else if($(this).hasClass("down")) {
                    //Do backend query and checking here (SET: error)
                    alert("Voted Down!");
                }
                //removes all the votes 
                $(this).parent("div").children().removeClass("current");

                if(!error) {
                    $(this).addClass("current");
                } else {
                    alert("There was an error");
                }
            }
            return false;
        });
    });
</script>
<div id="1234">
    <a class="vote up" href="#">+</a> | <a class="vote down" href="#">-</a>
</div>

It removes the need for extra html id's and you dont need the doubled up code to add the current class. I'm not sure which is quicker, but I think this way will allow better code maintenance.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...