Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
354 views
in Technique[技术] by (71.8m points)

c - pthread_cond_wait for 2 threads

I'm trying to implement pthread_cond_wait for 2 threads. My test code is trying to use two threads to preform the following scenario:

  • Thread B waits for condition
  • Thread A prints "Hello" five times
  • Thread A signals thread B
  • Thread A waits
  • Thread B prints "Goodbye"
  • Thread B signals thread A
  • Loop to start (x5)

So far the code prints "Hello" five times and then gets stuck. From examples I've looked at it seems I'm on the right track, "Lock mutex, wait, get signaled by other thread, unlock mutex, do stuff, loop"

Test Code:

//Import 
#include <stdio.h>
#include <stdlib.h>
#include <pthread.h>
#include <unistd.h>

//global variables
pthread_cond_t      condA  = PTHREAD_COND_INITIALIZER;
pthread_cond_t      condB  = PTHREAD_COND_INITIALIZER;
pthread_mutex_t     mutex = PTHREAD_MUTEX_INITIALIZER;




void *threadA()
{
    int i = 0, rValue, loopNum;

    while(i<5)
    {
        //unlock mutex
        rValue = pthread_mutex_unlock(&mutex);

        //do stuff
        for(loopNum = 1; loopNum <= 5; loopNum++)
            printf("Hello %d
", loopNum);

        //signal condition of thread b
        rValue = pthread_cond_signal(&condB);

        //lock mutex
        rValue = pthread_mutex_lock(&mutex);

        //wait for turn
        while( pthread_cond_wait(&condA, &mutex) != 0 )

        i++;
    }

}



void *threadB()
{
    int n = 0, rValue;

    while(n<5)
    {
        //lock mutex
        rValue = pthread_mutex_lock(&mutex);

        //wait for turn
        while( pthread_cond_wait(&condB, &mutex) != 0 )

        //unlock mutex
        rValue = pthread_mutex_unlock(&mutex);

        //do stuff
        printf("Goodbye");

        //signal condition a
        rValue = pthread_cond_signal(&condA);

        n++;        
    }
}




int main(int argc, char *argv[])
{
    //create our threads
    pthread_t a, b;

    pthread_create(&a, NULL, threadA, NULL);
    pthread_create(&b, NULL, threadB, NULL);

    pthread_join(a, NULL);
    pthread_join(b,NULL);
}

A pointer in the right direction would be greatly appreciated, thanks! (Code compiled on Linux using "gcc timeTest.c -o timeTest -lpthread")

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

You have two problems. The first is that you aren't using while() loops correctly - for example, here:

//wait for turn
while( pthread_cond_wait(&condA, &mutex) != 0 )

i++;

The body of the while loop is the statement i++ - this will execute pthread_cond_wait() and i++ until the pthread_cond_wait() returns an error, so this is essentially an endless loop.

The second is that you can't use a pthreads condition variable on its own - it needs to be paired with some actual shared state (at its simplest, this shared state might just be a flag variable protected by a mutex). The pthread_cond_wait() function is used to wait for the shared state to reach a certain value, and the pthread_cond_signal() function is used when a thread has altered the shared state. Reworking your example to use such a variable:

//global variables
/* STATE_A = THREAD A runs next, STATE_B = THREAD B runs next */
enum { STATE_A, STATE_B } state = STATE_A;
pthread_cond_t      condA  = PTHREAD_COND_INITIALIZER;
pthread_cond_t      condB  = PTHREAD_COND_INITIALIZER;
pthread_mutex_t     mutex = PTHREAD_MUTEX_INITIALIZER;

void *threadA()
{
    int i = 0, rValue, loopNum;

    while(i<5)
    {
        /* Wait for state A */
        pthread_mutex_lock(&mutex);
        while (state != STATE_A)
            pthread_cond_wait(&condA, &mutex);
        pthread_mutex_unlock(&mutex);

        //do stuff
        for(loopNum = 1; loopNum <= 5; loopNum++)
            printf("Hello %d
", loopNum);

        /* Set state to B and wake up thread B */
        pthread_mutex_lock(&mutex);
        state = STATE_B;
        pthread_cond_signal(&condB);
        pthread_mutex_unlock(&mutex);

        i++;
    }

    return 0;
}

void *threadB()
{
    int n = 0, rValue;

    while(n<5)
    {
        /* Wait for state B */
        pthread_mutex_lock(&mutex);
        while (state != STATE_B)
            pthread_cond_wait(&condB, &mutex);
        pthread_mutex_unlock(&mutex);

        //do stuff
        printf("Goodbye
");

        /* Set state to A and wake up thread A */
        pthread_mutex_lock(&mutex);
        state = STATE_A;
        pthread_cond_signal(&condA);
        pthread_mutex_unlock(&mutex);

        n++;
    }

    return 0;
}

Note that the use of two condition variables condA and condB is unnecessary here - the code would be just as correct if only one condition variable was used instead.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...