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python - How to make word boundary  not match on dashes

I simplified my code to the specific problem I am having.

import re
pattern = re.compile(r'word')
result = pattern.sub(lambda x: "match", "-word- word")

I am getting

'-match- match'

but I want

'-word- match'

edit:

Or for the string "word -word-"

I want

"match -word-"
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What you need is a negative lookbehind.

pattern = re.compile(r'(?<!-)word')
result = pattern.sub(lambda x: "match", "-word- word")

To cite the documentation:

(?<!...) Matches if the current position in the string is not preceded by a match for ....

So this will only match, if the word-break is not preceded with a minus sign -.

If you need this for the end of the string you'll have to use a negative lookahead which will look like this: (?!-). The complete regular expression will then result in: (?<!-)word(?!-)


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