Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
174 views
in Technique[技术] by (71.8m points)

c# - Why is decimal not a primitive type?

Why is decimal not a primitive type?

Console.WriteLine(typeof(decimal).IsPrimitive);

outputs false.

It is a base type, it's part of the specifications of the language, but not a primitive. What primitive type(s) do represent a decimal in the framework? An int for example has a field m_value of type int. A double has a field m_value of type double. It's not the case for decimal. It seems to be represented by a bunch of ints but I'm not sure.

Why does it look like a primitive type, behaves like a primitive type (except in a couple of cases) but is not a primitive type?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Although not a direct answer, the documentation for IsPrimitive lists what the primitive types are:

http://msdn.microsoft.com/en-us/library/system.type.isprimitive.aspx

A similar question was asked here:

http://bytes.com/topic/c-sharp/answers/233001-typeof-decimal-isprimitive-false-bug-feature

Answer quoted from Jon Skeet:

The CLR doesn't need to have any intrinsic knowledge about the decimal type - it treats it just as another value type which happens to have overloaded operators. There are no IL instructions to operate directly on decimals, for instance.

To me, it seems as though decimal is a type that must exist for a language/runtime wanting to be CLS/CLI-compliant (and is hence termed "primitive" because it is a base type with keyword support), but the actual implementation does not require it to be truly "primitive" (as in the CLR doesn't think it is a primitive data type).


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...