Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
241 views
in Technique[技术] by (71.8m points)

c++ - Should a buffer of bytes be signed or unsigned char buffer?

Should a buffer of bytes be signed char or unsigned char or simply a char buffer? Any differences between C and C++?

Thanks.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

If you intend to store arbitrary binary data, you should use unsigned char. It is the only data type that is guaranteed to have no padding bits by the C Standard. Each other data type may contain padding bits in its object representation (that is the one that contains all bits of an object, instead of only those that determines a value). The padding bits' state is unspecified and are not used to store values. So if you read using char some binary data, things would be cut down to the value range of a char (by interpreting only the value bits), but there may still be bits that are just ignored but still are there and read by memcpy. Much like padding bits in real struct objects. Type unsigned char is guaranteed to not contain those. That follows from 5.2.4.2.1/2 (C99 TC2, n1124 here):

If the value of an object of type char is treated as a signed integer when used in an expression, the value of CHAR_MIN shall be the same as that of SCHAR_MIN and the value of CHAR_MAX shall be the same as that of SCHAR_MAX. Otherwise, the value of CHAR_MIN shall be 0 and the value of CHAR_MAX shall be the same as that of UCHAR_MAX. The value UCHAR_MAX shall equal 2^CHAR_BIT ? 1

From the last sentence it follows that there is no space left for any padding bits. If you use char as the type of your buffer, you also have the problem of overflows: Assigning any value explicitly to one such element which is in the range of 8 bits - so you may expect such assignment to be OK - but not within the range of a char, which is CHAR_MIN..CHAR_MAX, such a conversion overflows and causes implementation defined results, including raise of signals.

Even if any problems regarding the above would probably not show in real implementations (would be a very poor quality of implementation), you are best to use the right type from the beginning onwards, which is unsigned char.

For strings, however, the data type of choice is char, which will be understood by string and print functions. Using signed char for these purposes looks like a wrong decision to me.

For further information, read this proposal which contain a fix for a next version of the C Standard which eventually will require signed char not have any padding bits either. It's already incorporated into the working paper.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...