windows 7 - How to use the start command in a batch file?

Question

I have a batch file that starts an app with a lot of command-line parameters:

"C:Program Files (x86)Common FilesMicrosoft SharedDevServer11.0WebDev.WebServer40.exe" /port:1672 /path:"C:Code.NetMy AppIteration 6REL_6.8.806_PerfEnhanceVFusionCodeCC.FusionCC.Fusion.Services" /vpath:"/FusionServices"

The problem is that when I run the batch file, the DOS window stays up until the command completes and I would like it to go away. So I tried using the start command, but placing it in front, like this:

start "C:Program Files (x86)Common FilesMicrosoft SharedDevServer11.0WebDev.WebServer40.exe" /port:1672 /path:"C:Code.NetMy AppIteration 6REL_6.8.806_PerfEnhanceVFusionCodeCC.FusionCC.Fusion.Services" /vpath:"/FusionServices"

But I get an error stating that Invalid switch - "/port:1672"

I have also tried escaping the double quotes, but I was not successful.

How do I fix that?

Answer 1

An extra pair of rabbits' ears should do the trick.

start "" "C:Program...

START regards the first quoted parameter as the window-title, unless it's the only parameter - and any switches up until the executable name are regarded as START switches.