Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
325 views
in Technique[技术] by (71.8m points)

increment row number when value of field changes in Oracle

I need help in writing a query in Oracle for the following data. The data is sorted by Person and Day fields.

    Person     Day   Flag
    ------     ---   ---- 
    person1    day1   Y
    person1    day2   Y
    person1    day3   Y
    person1    day4   N
    person1    day5   N
    person1    day6   Y
    person1    day7   Y
    person1    day8   Y

I need to have a Group_Number column that gets incremented whenever the Flag value changes. My result should look as below

    Person     Day   Flag  Group_Number
    ------     ---   ----  ------------
    person1    day1   Y    1
    person1    day2   Y    1
    person1    day3   Y    1
    person1    day4   N    2
    person1    day5   N    2
    person1    day6   Y    3
    person1    day7   Y    3
    person1    day8   Y    3

I think there is way to get above result using analytic functions such as ROW_NUMBER, LEAD etc.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

You can combine the analytic functions SUM (used as a running total) and LAG:

SQL> WITH data AS (
  2            SELECT 'person1' person, 'day1' day, 'Y' flag FROM dual
  3  UNION ALL SELECT 'person1' person, 'day2' day, 'Y' flag FROM dual
  4  UNION ALL SELECT 'person1' person, 'day3' day, 'Y' flag FROM dual
  5  UNION ALL SELECT 'person1' person, 'day4' day, 'N' flag FROM dual
  6  UNION ALL SELECT 'person1' person, 'day5' day, 'N' flag FROM dual
  7  UNION ALL SELECT 'person1' person, 'day6' day, 'Y' flag FROM dual
  8  UNION ALL SELECT 'person1' person, 'day7' day, 'Y' flag FROM dual
  9  UNION ALL SELECT 'person1' person, 'day8' day, 'Y' flag FROM dual
 10  )
 11  SELECT person, DAY, flag, SUM(gap) over (PARTITION BY person
 12                                           ORDER BY DAY) grp
 13    FROM (SELECT person, DAY, flag,
 14                 CASE WHEN flag = lag(flag) over (PARTITION BY person
 15                                                  ORDER BY DAY)
 16                      THEN 0
 17                      ELSE 1
 18                 END gap
 19            FROM DATA);

PERSON  DAY  FLAG        GRP
------- ---- ---- ----------
person1 day1 Y             1
person1 day2 Y             1
person1 day3 Y             1
person1 day4 N             2
person1 day5 N             2
person1 day6 Y             3
person1 day7 Y             3
person1 day8 Y             3

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...