This would be simple if your arrays contained only integers, but as they contain an another array, it gets a bit more complicated. But this should do it:
function custom_intersect($arrays) {
$comp = array_shift($arrays);
$values = array();
// The other arrays are compared to the first array:
// Get all the values from the first array for comparison
foreach($comp as $k => $v) {
// Set amount of matches for value to 1.
$values[$v['id']] = 1;
}
// Loop through the other arrays
foreach($arrays as $array) {
// Loop through every value in array
foreach($array as $k => $v) {
// If the current ID exists in the compare array
if(isset($values[$v['id']])) {
// Increase the amount of matches
$values[$v['id']]++;
}
}
}
$result = array();
// The amount of matches for certain value must be
// equal to the number of arrays passed, that's how
// we know the value is present in all arrays.
$n = count($arrays) + 1;
foreach($values as $k => $v) {
if($v == $n) {
// The value was found in all arrays,
// thus it's in the intersection
$result[] = $v;
}
}
return $result;
}
Usage:
$arrays = array(
array(array('id' => 3), array('id' => 1), array('id' => 2), array('id' => 5), array('id' => 4)),
array(array('id' => 1), array('id' => 3), array('id' => 4), array('id' => 5)),
array(array('id' => 3))
);
print_r(custom_intersect($arrays));
Result:
Array
(
[0] => 3
)
This function isn't perfect: if you have duplicate ID's in one array, it will not work. That would require a bit more code to first make the array values unique, but this will probably work in your case.
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