Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
509 views
in Technique[技术] by (71.8m points)

c++ - non-copyable objects and value initialization: g++ vs msvc

I'm seeing some different behavior between g++ and msvc around value initializing non-copyable objects. Consider a class that is non-copyable:

class noncopyable_base
{
public:
    noncopyable_base() {}

private:
    noncopyable_base(const noncopyable_base &);
    noncopyable_base &operator=(const noncopyable_base &);
};

class noncopyable : private noncopyable_base
{
public:
    noncopyable() : x_(0) {}
    noncopyable(int x) : x_(x) {}

private:
    int x_;
};

and a template that uses value initialization so that the value will get a known value even when the type is POD:

template <class T>
void doit()
{
    T t = T();
    ...
}

and trying to use those together:

doit<noncopyable>();

This works fine on msvc as of VC++ 9.0 but fails on every version of g++ I tested this with (including version 4.5.0) because the copy constructor is private.

Two questions:

  1. Which behavior is standards compliant?
  2. Any suggestion of how to work around this in gcc (and to be clear, changing that to T t; is not an acceptable solution as this breaks POD types).

P.S. I see the same problem with boost::noncopyable.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

The behavior you're seeing in MSVC is an extension, though it's documented as such in a roundabout way on the following page (emphasis mine) http://msdn.microsoft.com/en-us/library/0yw5843c.aspx:

The equal-sign initialization syntax is different from the function-style syntax, even though the generated code is identical in most cases. The difference is that when the equal-sign syntax is used, the compiler has to behave as if the following sequence of events were taking place:

  • Creating a temporary object of the same type as the object being initialized.
  • Copying the temporary object to the object.

The constructor must be accessible before the compiler can perform these steps. Even though the compiler can eliminate the temporary creation and copy steps in most cases, an inaccessible copy constructor causes equal-sign initialization to fail (under /Za, /Ze (Disable Language Extensions)).

See Ben Voigt's answer for a workaround which is a simplified version of boost::value_initialized, as pointed out by litb in a comment to Ben's answer. The docs for boost::value_initalized has a great discussion of the problem, the workaround, and some of the pitfalls of various compiler issues.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...