Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
301 views
in Technique[技术] by (71.8m points)

sql - Access top n in group

I have a table where I need to get the top n highest amount items for each Category.

Category Item  InventoryCount
-------  ----- ------------- 
Beverage  milk    3  
Beverage  water   2 
Beverage  beer    9 
Utensil   fork    7 
Utensil   spoon   2 
Utensil   knife   1 
Utensil   spork   4 

My desired output is the highest Inventory of the topmost 2 Categories.

Category Item  InventoryCount
-------  ----- ------------- 
Beverage  beer   9 
Beverage  milk   3 
Utensil   fork   7 
Utensil  spork   4 
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

This should work for you. If it doesn't satisfy your requirements, post back what you need. Your original desire was to have 25, so you'd simply modify the last clause to be HAVING COUNT(*) <= 25

SELECT  a.item, 
        a.category, 
        a.inventorycount, 
        COUNT(*) AS ranknumber
FROM inv AS a 
INNER JOIN inv AS b 
     ON (a.category = b.category) 
     AND (a.inventorycount <= b.inventorycount)
GROUP BY  a.category, 
          a.item, 
          a.inventorycount
HAVING COUNT(*) <= 2
ORDER BY a.category, COUNT(*) DESC

If you wanted to select more columns from the table, simply add them to the SELECT and `GROUP BY' clauses.

Only when you want to expand the "TOP n for each Category, foo, bar", then you would add those columns to the INNER JOIN clause as well.

--show the top 2 items for each category and year.
SELECT  a.item, 
        a.category, 
        a.year,
        a.inventorycount, 
        COUNT(*) AS ranknumber
FROM inv AS a 
INNER JOIN inv AS b 
     ON (a.category = b.category) 
     AND (a.year = b.year) 
     AND (a.inventorycount <= b.inventorycount)
GROUP BY  a.category, a.item, a.year, a.inventorycount
HAVING COUNT(*) <= 2
ORDER BY a.year, a.category, COUNT(*) DESC

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...