Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
393 views
in Technique[技术] by (71.8m points)

c# - Generic constraint ignores co-variance

Let's say we have an interface like

public interface IEnumerable<out T>
{ /*...*/ }

that is co-variant in T.

Then we have another interface and a class implementing it:

public interface ISomeInterface {}
public class SomeClass : ISomeInterface
{}

Now the co-variance allows us to do the following

IEnumerable<ISomeInterface> e = Enumerable.Empty<SomeClass>();

So a IEnumerable<SomeClass> is assignable to a variable (or method parameter) of type IEnumerable<ISomeInterface>.

But if we try this in a generic method:

public void GenericMethod<T>(IEnumerable<T> p) where T : ISomeInterface
{
    IEnumerable<ISomeInterface> e = p;
    // or
    TestMethod(p);
}
public void TestMethod(IEnumerable<ISomeInterface> x) {}

we get the compiler error CS0266 telling us that an IEnumerable<T> cannot be converted to an IEnumerable<ISomeInterface>.

The constraint clearly states the T is derived from ISomeInterface, and since IEnumerable<T> is co-variant in T, this assignment should work (as shown above).

Is there any technical reason why this cannot work in a generic method? Or anything I missed that makes it too expensive for the compiler to figure it out?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Change your GenericMethod and add generic constraint class:

public void GenericMethod<T>(IEnumerable<T> p) where T : class, ISomeInterface
{
    IEnumerable<ISomeInterface> e = p;
    // or
    TestMethod(p);
}

Covariance does not support structs, so we need to tell that we want to use classes only.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...