Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
218 views
in Technique[技术] by (71.8m points)

python - Understanding matplotlib verts

I'm trying to create custom markers in matplotlib for a scatter plot, where the markers are rectangles with fix height and varying width. The width of each marker is a function of the y-value. I tried it like this using this code as a template and assuming that if verts is given a list of N 2-D tuples it plots rectangles with the width of the corresponing first value and the height of the second (maybe this is already wrong, but then how else do I accomplish that?).

I have a list of x and y values, each containing angles in degrees. Then, I compute the width and height of each marker by

field_size = 2.
symb_vec_x = [(field_size / np.cos(i * np.pi / 180.)) for i in y]
symb_vec_y = [field_size for i in range(len(y))]

and build the verts list and plot everything with

symb_vec = list(zip(symb_vec_x, symb_vec_y))
fig = plt.figure(1, figsize=(14.40, 9.00))
ax = fig.add_subplot(1,1,1)
sc = ax.scatter(ra_i, dec_i, marker='None', verts=symb_vec)

But the resulting plot is empty, no error message however. Can anyone tell me what I did wrong with defining the verts and how to do it right? Thanks!

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

As mentioned 'marker='None' need to be removed then the appropriate way to specify a rectangle with verts is something like

verts = list(zip([-10.,10.,10.,-10],[-5.,-5.,5.,5]))
ax.scatter([0.5,1.0],[1.0,2.0], marker=(verts,0))

The vertices are defined as ([x1,x2,x3,x4],[y1,y2,y3,y4]) so attention must be paid to which get minus signs etc.

This (verts,0) is mentioned in the docs as

For backward compatibility, the form (verts, 0) is also accepted, but it is equivalent to just verts for giving a raw set of vertices that define the shape.

However I find using just verts does not give the correct shape.

To automate the process you need to do something like

v_val=1.0
h_val=2.0
verts = list(zip([-h_val,h_val,h_val,-h_val],[-v_val,-v_val,v_val,v_val]))

Basic example:

import pylab as py
ax = py.subplot(111)
v_val=1.0
h_val=2.0
verts = list(zip([-h_val,h_val,h_val,-h_val],[-v_val,-v_val,v_val,v_val]))
ax.scatter([0.5,1.0],[1.0,2.0], marker=(verts,0))

enter image description here*

edit

Individual markers

So you need to manually create a vert for each case. This will obviously depend on how you want your rectangles to change point to point. Here is an example

import pylab as py
ax = py.subplot(111)


def verts_function(x,y,r):
    # Define the vertex's multiplying the x value by a ratio
    x = x*r
    y = y
    return [(-x,-y),(x,-y),(x,y),(-x,y)]

n=5
for i in range(1,4):
    ax.scatter(i,i, marker=(verts_function(i,i,0.3),0))
    py.show()

enter image description here

so in my simple case I plot the points i,i and draw rectangles around them. The way the vert markers are specified is non intuitive. In the documentation it's described as follows:

verts: A list of (x, y) pairs used for Path vertices. The center of the marker is located at (0,0) and the size is normalized, such that the created path is encapsulated inside the unit cell.

Hence, the following are equivalent:

vert = [(-300.0, -1000), (300.0, -1000), (300.0, 1000), (-300.0, 1000)]
vert = [(-0.3, -1), (0.3, -1), (0.3, 1), (-0.3, 1)]

e.g they will produce the same marker. As such I have used a ratio, this is where you need to do put in the work. The value of r (the ratio) will change which axis remains constant.

This is all getting very complicated, I'm sure there must be a better way to do this.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...