Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
706 views
in Technique[技术] by (71.8m points)

algorithm - Shifting elements in an array C++

I've developed a method called "rotate" to my stack object class. What I did was that if the stack contains elements: {0,2,3,4,5,6,7} I would needed to rotate the elements forwards and backwards.

Where if i need to rotate forwards by 2 elements, then we would have, {3,4,5,6,7,0,2} in the array. And if I need to rotate backwards, or -3 elements, then, looking at the original array it would be, {5,6,7,0,2,3,4}

So the method that I have developed works fine. Its just terribly ineffecient IMO. I was wondering if I could wrap the array around by using the mod operator? Or if their is useless code hangin' around that I havent realized yet, and so on.

I guess my question is, How can i simplify this method? e.g. using less code. :-)

void stack::rotate(int r)
{
    int i = 0;
    while ( r > 0 ) // rotate postively.
    {
        front.n = items[top+1].n;
        for ( int j = 0; j < bottom; j++ )
        {
            items[j] = items[j+1];                                  
        }
        items[count-1].n = front.n;
        r--;
    }

    while ( r < 0 )  // rotate negatively.
    {
        if ( i == top+1 )
        {
            front.n = items[top+1].n;  
            items[top+1].n = items[count-1].n; // switch last with first
        }

        back.n = items[++i].n; // second element is the new back
        items[i].n = front.n; 
        if ( i == bottom )
        {
            items[count-1].n = front.n; // last is first
            i = 0;  
            r++;   
            continue;
        }
        else
        {
            front.n = items[++i].n;
            items[i].n  = back.n;
            if ( i == bottom )
            {
                i = 0;
                r++; 
                continue;
            }
        }
    }
}
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Instead of moving all the items in your stack, you could change the definition of 'beginning'. Have an index that represents the first item in the stack, 0 at the start, which you add to and subtract from using modular arithmetic whenever you want to rotate your stack.

Note that if you take this approach you shouldn't give users of your class access to the underlying array (not that you really should anyway...).


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...