Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
492 views
in Technique[技术] by (71.8m points)

dataframe - R: Pivoting using 'spread' function

Continuing from my previous post, I am now having 1 more column of ID values that I need to use to pivot rows into columns.

    NUM <- c(1,2,3,1,2,3,1,2,3,1)
    ID <- c("DJ45","DJ45","DJ45","DJ46","DJ46","DJ46","DJ47","DJ47","DJ47","DJ48")
    Type <- c("A", "F", "C", "B", "D", "A", "E", "C", "F", "D")
    Points <- c(9.2,60.8,22.9,1012.7,18.7,11.1,67.2,63.1,16.7,58.4)

    df1 <- data.frame(ID,NUM,Type,Points)

df1:
    +------+-----+------+--------+
    | ID   | Num | Type | Points |
    +------+-----+------+--------+
    | DJ45 |   1 | A    | 9.2    |
    | DJ45 |   2 | F    | 60.8   |
    | DJ45 |   3 | C    | 22.9   |
    | DJ46 |   1 | B    | 1012.7 |
    | DJ46 |   2 | D    | 18.7   |
    | DJ46 |   3 | A    | 11.1   |
    | DJ47 |   1 | E    | 67.2   |
    | DJ47 |   2 | C    | 63.1   |
    | DJ47 |   3 | F    | 16.7   |
    | DJ48 |   1 | D    | 58.4   |
    +------+-----+------+--------+

My desired output is

+------+-----+------+--------+------+------+------+------+
| ID   | Num |  A   |   B    |  C   |  D   |  E   |  F   |
+------+-----+------+--------+------+------+------+------+
| DJ45 |   1 | 9.2  | N/A    | N/A  | N/A  | N/A  | N/A  |
| DJ45 |   2 | N/A  | N/A    | N/A  | N/A  | N/A  | 60.8 |
| DJ45 |   3 | N/A  | N/A    | 22.9 | N/A  | N/A  | N/A  |
| DJ46 |   1 | N/A  | 1012.7 | N/A  | N/A  | N/A  | N/A  |
| DJ46 |   2 | N/A  | N/A    | N/A  | 18.7 | N/A  | N/A  |
| DJ46 |   3 | 11.1 | N/A    | N/A  | N/A  | N/A  | N/A  |
| DJ47 |   1 | N/A  | N/A    | N/A  | N/A  | 67.2 | N/A  |
| DJ47 |   2 | N/A  | N/A    | 63.1 | N/A  | N/A  | N/A  |
| DJ47 |   3 | N/A  | N/A    | N/A  | N/A  | N/A  | 16.7 |
| DJ48 |   1 | N/A  | N/A    | N/A  | 58.4 | N/A  | N/A  |
+------+-----+------+--------+------+------+------+------+

I am using spread function in R but getting errors saying duplicate identifiers. This is because I have 2 columns now (ID & NUM) instead of one (NUM) that I had previously. Please let me know how I could do this.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Not knowing what you've tried, I would suggest:

spread(df1, Type, Points)
#      ID NUM    A      B    C    D    E    F
# 1  DJ45   1  9.2     NA   NA   NA   NA   NA
# 2  DJ45   2   NA     NA   NA   NA   NA 60.8
# 3  DJ45   3   NA     NA 22.9   NA   NA   NA
# 4  DJ46   1   NA 1012.7   NA   NA   NA   NA
# 5  DJ46   2   NA     NA   NA 18.7   NA   NA
# 6  DJ46   3 11.1     NA   NA   NA   NA   NA
# 7  DJ47   1   NA     NA   NA   NA 67.2   NA
# 8  DJ47   2   NA     NA 63.1   NA   NA   NA
# 9  DJ47   3   NA     NA   NA   NA   NA 16.7
# 10 DJ48   1   NA     NA   NA 58.4   NA   NA

If you are getting an error about duplicate identifiers, it is because the combination of "ID" and "Num" in your actual data have one or more duplicate entries (in your sample data, they don't).

If that is the case, you need to add another column to make them unique.

Adding dplyr into the chain, it might be something like:

df1 %>%
  group_by(ID, NUM) %>%
  mutate(id2 = sequence(n())) %>%
  spread(Type, Points)

Demo of assumed error:

df2 <- rbind(df1, df1[1:3, ]) ## Duplicate the first three rows
spread(df2, Type, Points)
# Error: Duplicate identifiers for rows (1, 11), (3, 13), (2, 12)    

library(dplyr)

df2 %>%
  group_by(ID, NUM) %>%
  mutate(id2 = sequence(n())) %>%
  spread(Type, Points)
# Source: local data frame [13 x 9]
# 
#      ID NUM id2    A      B    C    D    E    F
# 1  DJ45   1   1  9.2     NA   NA   NA   NA   NA
# 2  DJ45   1   2  9.2     NA   NA   NA   NA   NA
# 3  DJ45   2   1   NA     NA   NA   NA   NA 60.8
# 4  DJ45   2   2   NA     NA   NA   NA   NA 60.8
# 5  DJ45   3   1   NA     NA 22.9   NA   NA   NA
# 6  DJ45   3   2   NA     NA 22.9   NA   NA   NA
# 7  DJ46   1   1   NA 1012.7   NA   NA   NA   NA
# 8  DJ46   2   1   NA     NA   NA 18.7   NA   NA
# 9  DJ46   3   1 11.1     NA   NA   NA   NA   NA
# 10 DJ47   1   1   NA     NA   NA   NA 67.2   NA
# 11 DJ47   2   1   NA     NA 63.1   NA   NA   NA
# 12 DJ47   3   1   NA     NA   NA   NA   NA 16.7
# 13 DJ48   1   1   NA     NA   NA 58.4   NA   NA

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...