Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
196 views
in Technique[技术] by (71.8m points)

python - Could random.randint(1,10) ever return 11?

When researching for this question and reading the sourcecode in random.py, I started wondering whether randrange and randint really behave as "advertised". I am very much inclined to believe so, but the way I read it, randrange is essentially implemented as

start + int(random.random()*(stop-start))

(assuming integer values for start and stop), so randrange(1, 10) should return a random number between 1 and 9.

randint(start, stop) is calling randrange(start, stop+1), thereby returning a number between 1 and 10.

My question is now:

If random() were ever to return 1.0, then randint(1,10) would return 11, wouldn't it?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

From random.py and the docs:

"""Get the next random number in the range [0.0, 1.0)."""

The ) indicates that the interval is exclusive 1.0. That is, it will never return 1.0.

This is a general convention in mathematics, [ and ] is inclusive, while ( and ) is exclusive, and the two types of parenthesis can be mixed as (a, b] or [a, b). Have a look at wikipedia: Interval (mathematics) for a formal explanation.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...