Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
439 views
in Technique[技术] by (71.8m points)

fortran - Is there anything wrong with passing an unallocated array to a routine without an explicit interface?

Consider:

program main
real, allocatable, dimension(:) :: foo
integer n
n=10
call dofoo(foo,n,1)
allocate(foo(n))
call dofoo(foo,n,0)
end program main

subroutine dofoo(foo,n,mode)
real foo(n)
integer i,n,mode
if(mode.eq.1)then
   n=6
   return
endif
do i=1,n
   foo(i)=i
enddo
return
end subroutine dofoo

Is there anything wrong with the above code? (It works with gfortran) I pass in an un-allocated array the first time, but I don't touch it -- Is there anything in the standard that could cause this to behave in a system dependent way?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

You've almost answered your own question. Yes, by the standard, it is always illegal to pass an unallocated allocatable arrays as an actual argument if you don't have an interface in scope.

If you have an interface in scope it is only legal if the dummy argument is also allocatable.

And yes I've been bitten by it. My work around has been to allocate to zero size before the call.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...