regex - Getting file extension using pattern matching in python

Question

I am trying to find the extension of a file, given its name as a string. I know I can use the function os.path.splitext but it does not work as expected in case my file extension is .tar.gz or .tar.bz2 as it gives the extensions as gz and bz2 instead of tar.gz and tar.bz2 respectively.
So I decided to find the extension of files myself using pattern matching.

print re.compile(r'^.*[.](?P<ext>tar.gz|tar.bz2|w+)$').match('a.tar.gz')group('ext')
>>> gz            # I want this to come as 'tar.gz'
print re.compile(r'^.*[.](?P<ext>tar.gz|tar.bz2|w+)$').match('a.tar.bz2')group('ext')
>>> bz2           # I want this to come 'tar.bz2'

I am using (?P<ext>...) in my pattern matching as I also want to get the extension.

Please help.

Answer 1

root,ext = os.path.splitext('a.tar.gz')
if ext in ['.gz', '.bz2']:
   ext = os.path.splitext(root)[1] + ext

_{Some people, when confronted with a problem, think "I know, I'll use regular expressions." Now they have two problems.}