Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
344 views
in Technique[技术] by (71.8m points)

python - TypeError: printName1() takes 0 positional arguments but 1 was given

So I have this very simple thing I wrote and it's killing me trying to figure out why it won't work. All it does it print a statement when you click.

So for the first example I had a button and assigned the function printName1 directly to it, which worked perfectly fine.

Then the next thing was to bind it using the .bind() function. So in this case we just have a frame that prints out certain things based on which button you press. But unfortunately whenever I use bind, it throws the error show above. References tkinter\__init__.py for the error, so it's not something directly in my code but maybe it needs to be done differently? Thanks guys.

from tkinter import *

root = Tk()

def printName1():
    print('Jack')

def printName2():
    print('John')

def printName3():
    print('Jill')

frame = Frame(root, width=300, height=250)
frame.bind("<Button-1>", printName1)
frame.bind("<Button-2>", printName2)
frame.bind("<Button-3>", printName3)
frame.pack()

root.mainloop()

EDIT: The error is confusing because it made it seem like there was an extra argument when there should be 0. But actually I needed to add an argument to the functions and that was event. so it should be def printName1(event) and so on. Just figured I would let you guys know what worked for me in case anyone stumbles upon this.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

If you refer to the documentation regarding tkinter events and bindings, you will see that when an event is triggered, the associated event object will be passed as the first (and only) argument to the bounded function (being printName1 and friends in your case).

So what you need to do is to modify those printName* functions to accept the event argument.

def printName1(event):
    print('Jack')

Then what you desired to achieve should work.

Naturally, you could make the event argument optional as @TigerhawkT3 suggested.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...