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ios - Image in TableViewCell swipe action

I have a swipe action to 'complete' a task in my to-do list app. This is the image I have set:

enter image description here

However when the cell is swiped, the image looks like this:

Swiped image

Is there a way to make the background transparent/white and the image to have the green circle like the image above?

If there is not, is there a way to make the green background 'wrap' to the purple of the cell so there is no whitespace? Thanks!

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by (71.8m points)

In came up with this extension for UIImage:

    extension UIImage {
        func colored(in color: UIColor) -> UIImage {
            let renderer = UIGraphicsImageRenderer(size: size)
            return renderer.image { context in
                color.set()
                self.withRenderingMode(.alwaysTemplate).draw(in: CGRect(origin: .zero, size: size))
            }
        }
    }

It returns a new icon in the new color when used like this:

        swipAction.image = UIImage(named: "myImage")?.colored(in: .white)

Maybe this helps someone.


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