Is there an easy, concise way to get a value from a nested dict and get None
if it's not there?
d1 = None
d2 = {}
d3 = {"a": {}}
d4 = {"a": {"b": 12345}}
ds = [d1, d2, d3, d4]
def nested_get(d):
# Is there a simpler concise one-line way to do exactly this, query a nested dict value, and return None if
# it doesn't exist?
a_val = d.get("a") if d else None
b_val = a_val.get("b") if a_val else None
return b_val
if __name__ == "__main__":
bs = [nested_get(d) for d in ds]
print("bs={}".format(bs))
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