Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
154 views
in Technique[技术] by (71.8m points)

c# - Xamarin: Upload image to server

I need upload image to server using api. Now I'm using System.Net.Http;

byte[] lFileBytes= DependencyService.Get<IFileHelper>().ReadAllBytes(ImagePath);
ByteArrayContent lFileContent = new ByteArrayContent(lFileBytes,0,lFileBytes.Length);
lFileContent.Headers.ContentDisposition = ContentDispositionHeaderValue.Parse("form-data");
lFileContent.Headers.ContentType=new MediaTypeHeaderValue("image/jpg");
lFileContent.Headers.ContentDisposition.Parameters.Add(new NameValueHeaderValue("name","file"));
lFileContent.Headers.ContentDisposition.Parameters.Add(new NameValueHeaderValue("filename", "9.jpg"));
lFileContent.Headers.ContentLength= lFileBytes.Length;
lContent.Add(lFileContent);

    public byte[] ReadAllBytes(string path) {
                using (var streamReader = new StreamReader(path))
                {
                    using (var memoryStream = new MemoryStream())
                    {
                        streamReader.BaseStream.CopyTo(memoryStream);
                        return memoryStream.ToArray();
                    }
                }
            }

After sending request i have error Type file is invalid I'm thinking problem in byte[] ReadAllBytes(string path) For request i can use Stream or byte[] Please, help UPDATE

 lRequestResponse = await lHttpClient.PostAsync("URL", lContent);
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

In case you still need, this works for me:

var cont = new MultipartFormDataContent();
var image = new StreamContent(img.Image.GetStream());
cont.Add(image, ""file"", img.FileName);
var uri = App.apiurl + $"FileUpload/" + img.FileName + "/";
using (var client = new HttpClient())
{
    var response = await client.PostAsync(uri, cont);
    if (response.StatusCode != System.Net.HttpStatusCode.OK)
    {
        // return error code
    }

}

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

1.4m articles

1.4m replys

5 comments

57.0k users

...