Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
240 views
in Technique[技术] by (71.8m points)

php - Libpuzzle Indexing millions of pictures?

its about the libpuzzle libray for php ( http://libpuzzle.pureftpd.org/project/libpuzzle ) from Mr. Frank Denis. I′am trying to understand how to index and store the data in my mysql database. The generation of the vector is absolutly no problem.

Example:

# Compute signatures for two images
$cvec1 = puzzle_fill_cvec_from_file('img1.jpg');
$cvec2 = puzzle_fill_cvec_from_file('img2.jpg');

# Compute the distance between both signatures
$d = puzzle_vector_normalized_distance($cvec1, $cvec2);

# Are pictures similar?
if ($d < PUZZLE_CVEC_SIMILARITY_LOWER_THRESHOLD) {
  echo "Pictures are looking similar
";
} else {
  echo "Pictures are different, distance=$d
";
}

Thats all clear to me - but now how do i work when i have a big amount of pictures >1.000.000? I calculate the vector and store it with the filename in the database? How to find the similar pictures now? If i store every vector in the mysql i have to open each record and calculate the distance with the puzzle_vector_normalized_distance function. That procedures takes alot of time (open each database entry - put it throw the function ,...)

I read the readme from the lib puzzle libaray and found the following:

Will it work with a database that has millions of pictures?

A typical image signature only requires 182 bytes, using the built-in compression/decompression functions.

Similar signatures share identical “words”, ie. identical sequences of values at the same positions. By using compound indexes (word + position), the set of possible similar vectors is dramatically reduced, and in most cases, no vector distance actually requires to get computed.

Indexing through words and positions also makes it easy to split the data into multiple tables and servers.

So yes, the Puzzle library is certainely not incompatible with projects that need to index millions of pictures.

Also i found this description about indexing:

------------------------ INDEXING ------------------------

How to quickly find similar pictures, if they are millions of records?

The original paper has a simple, yet efficient answer.

Cut the vector in fixed-length words. For instance, let's consider the following vector:

[ a b c d e f g h i j k l m n o p q r s t u v w x y z ]

With a word length (K) of 10, you can get the following words:

[ a b c d e f g h i j ] found at position 0 [ b c d e f g h i j k ] found at position 1 [ c d e f g h i j k l ] found at position 2 etc. until position N-1

Then, index your vector with a compound index of (word + position).

Even with millions of images, K = 10 and N = 100 should be enough to have very little entries sharing the same index.

Here's a very basic sample database schema:

+-----------------------------+
| signatures |
+-----------------------------+
| sig_id | signature | pic_id |
+--------+-----------+--------+

+--------------------------+
| words |
+--------------------------+
| pos_and_word | fk_sig_id |
+--------------+-----------+

I'd recommend splitting at least the "words" table into multiple tables and/or servers.

By default (lambas=9) signatures are 544 bytes long. In order to save storage space, they can be compressed to 1/third of their original size through the puzzle_compress_cvec() function. Before use, they must be uncompressed with puzzle_uncompress_cvec().

I think that compressing is the wrong way cause then i have to uncompress every vector before comparing it.

My question is now - whats the way to handle millions of pictures and how to compare them in a fast and efficient way. I cant understand how the "cutting of the vector" should help me with my problem.

Many thanks - maybe i can find someone here which is working with the libpuzzle libaray.

Cheers.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

So, let's take a look at the example they give and try to expand.

Let's assume you have a table that stores information relating to each image (path, name, description, etc). In that table, you'll include a field for the compressed signature, calculated and stored when you initially populate the database. Let's define that table thus:

CREATE TABLE images (
    image_id INTEGER NOT NULL PRIMARY KEY,
    name TEXT,
    description TEXT,
    file_path TEXT NOT NULL,
    url_path TEXT NOT NULL,
    signature TEXT NOT NULL
);

When you initially compute the signature, you're also going to compute a number of words from the signature:

// this will be run once for each image:
$cvec = puzzle_fill_cvec_from_file('img1.jpg');
$words = array();
$wordlen = 10; // this is $k from the example
$wordcnt = 100; // this is $n from the example
for ($i=0; $i<min($wordcnt, strlen($cvec)-$wordlen+1); $i++) {
    $words[] = substr($cvec, $i, $wordlen);
}

Now you can put those words into a table, defined thus:

CREATE TABLE img_sig_words (
    image_id INTEGER NOT NULL,
    sig_word TEXT NOT NULL,
    FOREIGN KEY (image_id) REFERENCES images (image_id),
    INDEX (image_id, sig_word)
);

Now you insert into that table, prepending the position index of where the word was found, so that you know when a word matches that it matched in the same place in the signature:

// the signature, along with all other data, has already been inserted into the images
// table, and $image_id has been populated with the resulting primary key
foreach ($words as $index => $word) {
    $sig_word = $index.'__'.$word;
    $dbobj->query("INSERT INTO img_sig_words (image_id, sig_word) VALUES ($image_id,
        '$sig_word')"); // figure a suitably defined db abstraction layer...
}

Your data thus initialized, you can grab images with matching words relatively easily:

// $image_id is set to the base image that you are trying to find matches to
$dbobj->query("SELECT i.*, COUNT(isw.sig_word) as strength FROM images i JOIN img_sig_words
    isw ON i.image_id = isw.image_id JOIN img_sig_words isw_search ON isw.sig_word =
    isw_search.sig_word AND isw.image_id != isw_search.image_id WHERE
    isw_search.image_id = $image_id GROUP BY i.image_id, i.name, i.description,
    i.file_path, i.url_path, i.signature ORDER BY strength DESC");

You could improve the query by adding a HAVING clause that requires a minimum strength, thus further reducing your matching set.

I make no guarantees that this is the most efficient setup, but it should be roughly functional to accomplish what you're looking for.

Basically, splitting and storing the words in this manner allows you to do a rough distance check without having to run a specialized function on the signatures.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...