Let's write both in binary:
130.45.34.36 = 10000010.00101101.00100010.00100100
255.255.240.0 = 11111111.11111111.11110000.00000000
A bitwise AND between the two would give us the network address:
10000010.00101101.00100010.00100100 (ip address)
AND
11111111.11111111.11110000.00000000 (subnet mask)
=
10000010.00101101.00100000.00000000 = 130.45.32.0 (the resulting network address)
A bitwise OR between the network address and the inverted subnet mask would give us the broadcast address:
10000010.00101101.00100000.00000000 (netadress)
OR
00000000.00000000.00001111.11111111 (inverted subnet mask)
=
10000010.00101101.00101111.11111111 = 130.45.47.255 (broadcast address)
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