js 实现两个数组（一个数组包含于另一个数组中）去重的问题

Question

arr2是arr1的子数组，（也就是说arr2中的元素arr1都有）现在要得到在arr1中删除arr2中出现的元素后的结果，各位大神有什么好办法

    var arr1 = [
        {id:1,name:'a'},
        {id:2,name:'abc'},
        {id:3,name:'abbb'}, 
        {id:4,name:'abxxx'}, 
        {id:5,name:'xyz'},
        {id:6,name:'abcdef'},
        {id:7,name:'abzzzz'}];
    var arr2 = [
        {id:1,name:'a'},
        {id:5,name:'xyz'},
        {id:7,name:'abzzzz'}];

Answer 1

var result = arr1.filter(function(item1) {
    return arr2.every(function(item2) {
        return item2.id !== item1.id
    })
})