Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
895 views
in Technique[技术] by (71.8m points)

python - asyncio.run() cannot be called from a running event loop

I would like to use asyncio to get webpage html.

I run the following code in jupyter notebook:

import aiofiles
import aiohttp
from aiohttp import ClientSession

async def get_info(url, session):
    resp = await session.request(method="GET", url=url)
    resp.raise_for_status()
    html = await resp.text(encoding='GB18030')
    with open('test_asyncio.html', 'w', encoding='utf-8-sig') as f:
        f.write(html)
    return html
    
async def main(urls):
    async with ClientSession() as session:
        tasks = [get_info(url, session) for url in urls]
        return await asyncio.gather(*tasks)

if __name__ == "__main__":
    url = ['http://huanyuntianxiazh.fang.com/house/1010123799/housedetail.htm', 'http://zhaoshangyonghefu010.fang.com/house/1010126863/housedetail.htm']
    result = asyncio.run(main(url))

However, it returns RuntimeError: asyncio.run() cannot be called from a running event loop

What is the problem?

How to solve it?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

The asyncio.run() documentation says:

This function cannot be called when another asyncio event loop is running in the same thread.

In your case, jupyter (IPython ≥ 7.0) is already running an event loop:

You can now use async/await at the top level in the IPython terminal and in the notebook, it should?—?in most of the cases?—?“just work”. Update IPython to version 7+, IPykernel to version 5+, and you’re off to the races.

Therefore you don't need to start the event loop yourself and can instead call await main(url) directly, even if your code lies outside any asynchronous function.

Jupyter / IPython

async def main():
    print(1)
    
await main()

Python (≥ 3.7)

import asyncio

async def main():
    print(1)
    
asyncio.run(main())

In your code that would give:

url = ['url1', 'url2']
result = await main(url)

for text in result:
    pass # text contains your html (text) response

Caution

There is a slight difference on how Jupyter use the loop compared to IPython.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...