Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
577 views
in Technique[技术] by (71.8m points)

jquery - Positive Number to Negative Number in JavaScript?

Basically, the reverse of abs. If I have:

if ($this.find('.pdxslide-activeSlide').index() < slideNum - 1) {
  slideNum = -slideNum
}
console.log(slideNum)

No matter what console always returns a positive number. How do I fix this?

If I do:

if ($this.find('.pdxslide-activeSlide').index() < slideNum - 1) {
  _selector.animate({
    left: (-slideNum * sizes.images.width) + 'px'
  }, 750, 'InOutPDX')
} else {
  _selector.animate({
    left: (slideNum * sizes.images.width) + 'px'
  }, 750, 'InOutPDX')
}

it works tho, but it's not "DRY" and just stupid to have an entire block of code JUST for a -.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)
Math.abs(num) => Always positive
-Math.abs(num) => Always negative

You do realize however, that for your code

if($this.find('.pdxslide-activeSlide').index() < slideNum-1){ slideNum = -slideNum }
console.log(slideNum)

If the index found is 3 and slideNum is 3,
then 3 < 3-1 => false
so slideNum remains positive??

It looks more like a logic error to me.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...