Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
1.0k views
in Technique[技术] by (71.8m points)

shell - Calling one Bash script from another Script passing it arguments with quotes and spaces

I made two test bash scripts on Linux to make the problem clear.

TestScript1 looks like:
    echo "TestScript1 Arguments:"
    echo "$1"
    echo "$2"
    echo "$#"
    ./testscript2 $1 $2
TestScript2 looks like:
    echo "TestScript2 Arguments received from TestScript1:"
    echo "$1"
    echo "$2"
    echo "$#"
When i execute testscript1 in the following way:
    ./testscript1 "Firstname Lastname" [email protected]  
The desired Output should be:
    TestScript1 Arguments:  
    Firstname Lastname  
    [email protected]  
    2
    TestScript2 Arguments received from TestScript1:  
    Firstname Lastname  
    [email protected]  
    2  
But the actual output is:
    TestScript1 Arguments:  
    Firstname Lastname  
    [email protected]  
    2
    TestScript2 Arguments received from TestScript1:  
    Firstname
    Lastname      
    3  

How do i solve this problem? I want to get the desired output instead of the actual output.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Quote your args in Testscript 1:

echo "TestScript1 Arguments:"
echo "$1"
echo "$2"
echo "$#"
./testscript2 "$1" "$2"

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...