Scenario: Web form for developer app registration with two part workflow.
Page 1: Fill out developer app details and click on button to create Application ID, which opens, in a new tab...
Page 2: The App ID page. I need to copy the App ID from this page, then close the tab and go back to Page 1 and fill in the App ID (saved from Page 2), then submit the form.
I understand basic usage - how to open Page 1 and click the button which opens Page 2 - but how do I get a handle on Page 2 when it opens in a new tab?
Example:
const puppeteer = require('puppeteer');
(async() => {
const browser = await puppeteer.launch({headless: false, executablePath: '/Applications/Google Chrome.app'});
const page = await browser.newPage();
// go to the new bot registration page
await page.goto('https://register.example.com/new', {waitUntil: 'networkidle'});
// fill in the form info
const form = await page.$('new-app-form');
await page.focus('#input-appName');
await page.type('App name here');
await page.focus('#input-appDescription');
await page.type('short description of app here');
await page.click('.get-appId'); //opens new tab with Page 2
// handle Page 2
// get appID from Page 2
// close Page 2
// go back to Page 1
await page.focus('#input-appId');
await page.type(appIdSavedFromPage2);
// submit the form
await form.evaluate(form => form.submit());
browser.close();
})();
Update 2017-10-25
Still looking for a good usage example.
See Question&Answers more detail:
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