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jquery - .attr('checked','checked') does not work

I am trying to check radio. Neither the following works:

[edit]

$('selector').attr('checked','checked');
$('selector').attr('checked',true);

The two alert() in the following code show "1" and "a", respectively. My expectation is the second alert() showing "b".

Opera does check the second radio box in its browser, but its element inspector, dragonfly, shows that the DOM is not changed.

[end edit]

I had read the FAQ before I posted this question:

http://docs.jquery.com/Frequently_Asked_Questions#How_do_I_check.2Funcheck_a_checkbox_input_or_radio_button.3F

Helps will be much appreciated!

TIA

The xhtml page and code follows:

<!DOCTYPE html 
     PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
     "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8"/>
<title>Weird Behavior</title>
<script type="text/javascript" src="scripts/jquery.js"/>
<script type="text/javascript">
function clickme(){
    alert($('input[name="myname"][value="b"]').length);
    $('input[name="myname"][value="b"]').attr('checked','checked');
    $('#b').attr('checked',true);
    alert($('input[name="myname"][checked]').val());
};
</script>
</head>
<body>
    <form action="">
        <fieldset>
            <legend>Why check is not switched?</legend>
            <input type="radio" name="myname" value="a" id="a" checked="checked"/>A
            <input type="radio" name="myname" value="b" id="b"/>B
        </fieldset>
    </form>
    <p>
    <button type="button" onclick="clickme()">click me</button>
    </p>
</body>
</html>
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1 Reply

0 votes
by (71.8m points)
 $('.checkbox').attr('checked',true);

will not work with from jQuery 1.6.

Instead use

$('.checkbox').prop('checked',true);
$('.checkbox').prop('checked',false);

Full explanation / examples and demo can be found in the jQuery API Documentation https://api.jquery.com/attr/


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