Using re.findall but without parenthesis in Python

Question

I have a variable in python x, storing below values :

XYZ (APABC01)
ABC (ACACA18)
GHI (ABUAD21)

I want only the part which is inside the parenthesis as a list. I have used below regex and I almost got it correct :

re.findall('((.*?))',x)

Output is:

['APABC01)', 'ACACA18)', 'ABUAD21)']

My question is how can I eliminate the other parenthesis. I want the output like :

['APABC01', 'ACACA18', 'ABUAD21']

so that i can access my elements in the list for further usage

Answer 1

Use this regex:

import re

x = '''XYZ (APABC01)
ABC (ACACA18)
GHI (ABUAD21)
'''
print(re.findall(r'[(](.*?)[)]', x))
# ['APABC01', 'ACACA18', 'ABUAD21']

[(] : Character class that consists of only ( - the opening parens. You can also use ( - escaped opening parens instead.
(.*?) : Any character repeated 0 or more times, non-greedy (the minimum number of occurrences). The pattern is captured and returned as a list by re.findall.