Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
298 views
in Technique[技术] by (71.8m points)

javascript - jQuery appending an array of elements

For the purpose of this question lets say we need to append() 1000 objects to the body element.

You could go about it like this:

for(x = 0; x < 1000; x++) {
    var element = $('<div>'+x+'</div>');
    $('body').append(element);
}

This works, however it seems inefficient to me as AFAIK this will cause 1000 document reflows. A better solution would be:

var elements = [];
for(x = 0; x < 1000; x++) {
    var element = $('<div>'+x+'</div>');
    elements.push(element);
}
$('body').append(elements);

However this is not an ideal world and this throws an error Could not convert JavaScript argument arg 0 [nsIDOMDocumentFragment.appendChild]. I understand that append() can't handle arrays.

How would I using jQuery (I know about the DocumentFragment node, but assume I need to use other jQuery functions on the element such as .css()) add a bunch of objects to the DOM at once to improve performance?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

You could use an empty jQuery object instead of an array:

var elements = $();
for(x = 0; x < 1000; x++) {
    elements = elements.add('<div>'+x+'</div>');
    // or 
    // var element = $('<div>'+x+'</div>');
    // elements = elements.add(element);
}
$('body').append(elements);

This might be useful if you want to do stuff with newly generated element inside the loop. But note that this will create a huge internal stack of elements (inside the jQuery object).


It seems though that your code works perfectly fine with jQuery 1.8.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...