postgresql - How do I use spring data jpa to query jsonb column?

Question

I'm having a problem getting this native query right against a postgres 9.4 instance.

My repository has a method:

 @Query(value = "SELECT t.* " +
            "FROM my_table t " +
            "WHERE t.field_1 = ?1 " +
            "AND t.field_2 = 1 " +
            "AND t.field_3 IN ?2 " +
            "AND t.jsonb_field #>> '{key,subkey}' = ?3",
            nativeQuery = true)
    List<Entity> getEntities(String field1Value,
                                   Collection<Integer> field3Values,
                                   String jsonbFieldValue);

But the logs show this:

SELECT t.* FROM my_table t 
WHERE t.field_1 = ?1 
  AND t.field_2 = 1 
  AND t.field_3 IN ?2 
  AND t.jsonb_field ? '{key,subkey}' = ?3

And I get this exception:

Internal Exception: org.postgresql.util.PSQLException: No value specified for parameter 2.

I logged the parameters directly before method invocation, and they are all supplied.

I'm not sure why #>> shows ? in the log. Do I need to escape #>>? Do I need to format the collection for IN? Do I need to escape the json path?

When I execute the query directly against the db, it works. Example:

SELECT *
FROM my_table t
WHERE t.field_1 = 'xxxx'
  AND t.field_2 = 1
  AND t.field_3 IN (13)
  AND t.jsonb_field #>> '{key,subkey}' = 'value'

Answer 1

I found very helpful the Specification api from spring data.
Let's say we have an entity with name Product and a property with name title of type JSON(B).
I assume that this property contains the title of the Product in different languages. An example could be: {"EN":"Multicolor LED light", "EL":"Πολ?χρωμο LED φ??"}.
The source code below finds a (or more in case it is not a unique field) product by title and locale passed as arguments.

@Repository
public interface ProductRepository extends JpaRepository<Product, Integer>, JpaSpecificationExecutor<Product> {
}


public class ProductSpecification implements Specification<Product> {

    private String locale;
    private String titleToSearch;

    public ProductSpecification(String locale, String titleToSearch) {
        this.locale = locale;
        this.titleToSearch = titleToSearch;
    }

    @Override
    public Predicate toPredicate(Root<Product> root, CriteriaQuery<?> query, CriteriaBuilder builder) {
        return builder.equal(builder.function("jsonb_extract_path_text", String.class, root.<String>get("title"), builder.literal(this.locale)), this.titleToSearch);
    }
}


@Service
public class ProductService {

    @Autowired
    private ProductRepository productRepository;

    public List<Product> findByTitle(String locale, String titleToSearch) {
        ProductSpecification cs = new ProductSpecification(locale, titleToSearch);
        return productRepository.find(cs);
        // Or using lambda expression - without the need of ProductSpecification class.
//      return productRepository.find((Root<ProductCategory> root, CriteriaQuery<?> query, CriteriaBuilder builder) -> {
//          return builder.equal(builder.function("jsonb_extract_path_text", String.class, root.<String>get("title"), builder.literal(locale)), titleToSearch);
//      });
    }
}

You can find another answer about the way you should use the Spring Data here.
Hope that helps.