go - How do I unpack various form of integers in a byte buffer in Golang?

Question

I need to extract various fields in a byte buffer. I came up with this solution:

func (fs *FileSystem) readSB() {
    // fs.f is a *os.File
    buf := make([]byte, 1024)
    fs.f.ReadAt(buf, 1024)

    // Offset: type
    var p *bytes.Buffer

    // 0: uint32
    p = bytes.NewBuffer(buf[0:])
    binary.Read(p, binary.LittleEndian, &fs.sb.inodeCount)
    // 4: uint32
    p = bytes.NewBuffer(buf[4:])
    binary.Read(p, binary.LittleEndian, &fs.sb.blockCount)
    // 20: uint32
    p = bytes.NewBuffer(buf[20:])
    binary.Read(p, binary.LittleEndian, &fs.sb.firstDataBlock)
    // 24: uint32
    p = bytes.NewBuffer(buf[24:])
    binary.Read(p, binary.LittleEndian, &fs.sb.blockSize)
    fs.sb.blockSize = 1024 << fs.sb.blockSize
    // 32: uint32
    p = bytes.NewBuffer(buf[32:])
    binary.Read(p, binary.LittleEndian, &fs.sb.blockPerGroup)
    // 40: uint32
    p = bytes.NewBuffer(buf[40:])
    binary.Read(p, binary.LittleEndian, &fs.sb.inodePerBlock)
}

Is there a more better/idiomatic/straightforward way of doing this?

• I want to keep offsets explicit
• I want to read from the byte buffer, not seeking and reading from the file when possible.

Answer 1

Waitting for answers