Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
584 views
in Technique[技术] by (71.8m points)

python - Rotated image coordinates after scipy.ndimage.interpolation.rotate?

I have a numpy array for an image that I read in from a FITS file. I rotated it by N degrees using scipy.ndimage.interpolation.rotate. Then I want to figure out where some point (x,y) in the original non-rotated frame ends up in the rotated image -- i.e., what are the rotated frame coordinates (x',y')?

This should be a very simple rotation matrix problem but if I do the usual mathematical or programming based rotation equations, the new (x',y') do not end up where they originally were. I suspect this has something to do with needing a translation matrix as well because the scipy rotate function is based on the origin (0,0) rather than the actual center of the image array.

Can someone please tell me how to get the rotated frame (x',y')? As an example, you could use

from scipy import misc
from scipy.ndimage import rotate
data_orig = misc.face()
data_rot = rotate(data_orig,66) # data array
x0,y0 = 580,300 # left eye; (xrot,yrot) should point there

P.S. The following two related questions' answers do not help me:

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

As usual with rotations, one needs to translate to the origin, then rotate, then translate back. Here, we can take the center of the image as origin.

import numpy as np
import matplotlib.pyplot as plt
from scipy import misc
from scipy.ndimage import rotate

data_orig = misc.face()
x0,y0 = 580,300 # left eye; (xrot,yrot) should point there

def rot(image, xy, angle):
    im_rot = rotate(image,angle) 
    org_center = (np.array(image.shape[:2][::-1])-1)/2.
    rot_center = (np.array(im_rot.shape[:2][::-1])-1)/2.
    org = xy-org_center
    a = np.deg2rad(angle)
    new = np.array([org[0]*np.cos(a) + org[1]*np.sin(a),
            -org[0]*np.sin(a) + org[1]*np.cos(a) ])
    return im_rot, new+rot_center


fig,axes = plt.subplots(2,2)

axes[0,0].imshow(data_orig)
axes[0,0].scatter(x0,y0,c="r" )
axes[0,0].set_title("original")

for i, angle in enumerate([66,-32,90]):
    data_rot, (x1,y1) = rot(data_orig, np.array([x0,y0]), angle)
    axes.flatten()[i+1].imshow(data_rot)
    axes.flatten()[i+1].scatter(x1,y1,c="r" )
    axes.flatten()[i+1].set_title("Rotation: {}deg".format(angle))

plt.show()

enter image description here


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...