For a bitmask, the type bitstring
would be the better choice. Could look like this then:
SELECT BoolD::int::bit
|| BoolC::int::bit
|| BoolB::int::bit
|| BoolA::int::bit
FROM tbl;
TRUE
converts to 1
, FALSE
to 0
. You can simply concatenate bits to a bitstring.
Cast bit(n) to integer
It seems you need an integer
as result - there is a simple & fast way:
SELECT (BoolD::int::bit
|| BoolC::int::bit
|| BoolB::int::bit
|| BoolA::int::bit)::bit(4)::int
FROM tbl;
Be sure to read the fine print in the chapter "Bit String Functions and Operators" of the manual.
I came up with two more ideas and put together a quick test / reference with 10k rows to sum it all up.
Test setup:
CREATE TEMP TABLE t (boola bool, boolb bool, boolc bool, boold bool);
INSERT INTO t
SELECT random()::int::bool
, random()::int::bool
, random()::int::bool
, random()::int::bool
FROM generate_series(1,10000);
Demo:
SELECT CASE WHEN boold THEN 1 ELSE 0 END
+ (CASE WHEN boolc THEN 1 ELSE 0 END << 1)
+ (CASE WHEN boolb THEN 1 ELSE 0 END << 2)
+ (CASE WHEN boola THEN 1 ELSE 0 END << 3) AS andriy
, boold::int
+ (boolc::int << 1)
+ (boolb::int << 2)
+ (boola::int << 3) AS mike
, (boola::int::bit
|| boolb::int::bit
|| boolc::int::bit
|| boold::int::bit)::bit(4)::int AS erwin1
, boold::int
| (boolc::int << 1)
| (boolb::int << 2)
| (boola::int << 3) AS erwin2
, (((
boola::int << 1)
| boolb::int << 1)
| boolc::int << 1)
| boold::int AS erwin3
FROM t
LIMIT 15
You could also use a bitwise OR |
instead of the +
operator.
Individual test runs show basically the same performance for all five methods.
与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…