Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
1.0k views
in Technique[技术] by (71.8m points)

python - BeautifulSoup: How do I extract all the <li>s from a list of <ul>s that contains some nested <ul>s?

My source code looks like:

<h3>Header3 (Start here)</h3>
<ul>
    <li>List items</li>
    <li>Etc...</li>
</ul>
<h3>Header 3</h3>
<ul>
    <li>List items</li>
    <ul>
        <li>Nested list items</li>
        <li>Nested list items</li></ul>
    <li>List items</li>
</ul>
<h2>Header 2 (end here)</h2>

I'd like all the "li" tags following the first "h3" tag and stopping at the next "h2" tag, including all nested li tags.

firstH3 = soup.find('h3')

correctly finds the place I'd like to start.

firstH3 = soup.find('h3') # Start here
uls = []
for nextSibling in firstH3.findNextSiblings():
    if nextSibling.name == 'h2':
        break
    if nextSibling.name == 'ul':
        uls.append(nextSibling)

gives me a list of ULs, each with LI contents that I need.

EXCERPT OF THE "uls" LIST:

<ul>
...
    <li><i><a href="/wiki/Agent_Cody_Banks" title="Agent Cody Banks">Agent Cody Banks</a></i> (2003)</li>
    <li><i><a href="/wiki/Agent_Cody_Banks_2:_Destination_London" title="Agent Cody Banks 2: Destination London">Agent Cody Banks 2: Destination London</a></i> (2004)</li>
    <li>Air Bud series:
        <ul>
            <li><i><a href="/wiki/Air_Bud:_World_Pup" title="Air Bud: World Pup">Air Bud: World Pup</a></i> (2000)</li>
            <li><i><a href="/wiki/Air_Bud:_Seventh_Inning_Fetch" title="Air Bud: Seventh Inning Fetch">Air Bud: Seventh Inning Fetch</a></i> (2002)</li>
            <li><i><a href="/wiki/Air_Bud:_Spikes_Back" title="Air Bud: Spikes Back">Air Bud: Spikes Back</a></i> (2003)</li>
            <li><i><a href="/wiki/Air_Buddies" title="Air Buddies">Air Buddies</a></i> (2006)</li>
        </ul>
    </li>
    <li><i><a href="/wiki/Akeelah_and_the_Bee" title="Akeelah and the Bee">Akeelah and the Bee</a></i> (2006)</li>
...
</ul>

But I'm unsure of where to go from here. I'm a newbie programmer trying to jump in to Python by building a script that scrapes http://en.wikipedia.org/wiki/2000s_in_film and extracts a list of "Movie Title (Year)".


Update:

Final Code:

lis = []
    for ul in uls:
        for li in ul.findAll('li'):
            if li.find('ul'):
                break
            lis.append(li)

    for li in lis:
        print li.text.encode("utf-8")

The If-->break throws out the LI's that contain UL's since the nested LI's are now duplicated.

Print output is now:

  • 102 Dalmatians(2000)
  • 10th & Wolf(2006)
  • 11:14(2006)
  • 12:08 East of Bucharest(2006)
  • 13 Going on 30(2004)
  • 1408(2007)
  • ...

Thanks

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

.findAll() works for nested li elements:

for ul in uls:
    for li in ul.findAll('li'):
        print(li)

Output:

<li>List items</li>
<li>Etc...</li>
<li>List items</li>
<li>Nested list items</li>
<li>Nested list items</li>
<li>List items</li>

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

1.4m articles

1.4m replys

5 comments

57.0k users

...