Sorted a list contains tuple in Python

Question

I have a list like this:

list = [('Betty', 42.5), ('Andrew', 46.5), ('Zach', 49), ('Cathy',     
42.5), ('Jay', 45.5), ('Kevin', 45), ('Cassie', 41), ('Matt', 44),     
('Jamie', 44.5), ('Xavier', 45.5), ('Peter', 45.5), ('John', 42.5), 
('Jamie', 40.5), ('Joe', 40.5), ('Ellen', 44.5), ('Nancy', 35), 
('Jay', 45), ('Bryce', 43.5), ('Gordon', 37), ('Gee', 42.5)]```

How I can sort it by name (if name is same, the one with higher score comes first) in Python?

I tried this but it doesn't sort by score if same name sorted(list)

Answer 1

lst = [('Betty', 42.5), ('Andrew', 46.5), ('Zach', 49), ('Cathy', 42.5), ('Jay', 45.5), ('Kevin', 45), ('Cassie', 41), ('Matt', 44), ('Jamie', 44.5), ('Xavier', 45.5), ('Peter', 45.5), ('John', 42.5), ('Jamie', 40.5), ('Joe', 40.5), ('Ellen', 44.5), ('Nancy', 35), ('Jay', 45), ('Bryce', 43.5), ('Gordon', 37), ('Gee', 42.5)]

n0 = sorted(lst, key=lambda x: x[1],reverse=True) 
n1 = sorted(n0, key=lambda x: x[0])
print(n1)