Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
494 views
in Technique[技术] by (71.8m points)

lag function doesn't work in SAS

Here is the part of my program.(oldindex and oldreadmit is in retain commend)

The problem is it works for oldindex=1 then readmit=1 but doesn't work lag(oldreadmit)=1 then readmit=1. Could you tell what's the problem? Thanks in advance!

else if 0< gap <= 30 then do;
     index_d=0;
     if lag(oldreadmit)=1 or oldindex=1  then readmit=1;
         else oth=1;
     oldindex=index_d; 
     oldreadmit=readmit;
     end;

Jane

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

The SAS lag function is a cause for much confusion, but once you understand how it works it makes sense. Suppose you have 3 observations, and you have an if statement that causes the second observation to be skipped during processing. If you then apply the lag function to the third observation, it will return the first observation, not the second, because the last time any observation was processed was for the first observation.

What this means is, be careful when combining lags and if statements. In your code, you have a lag in a clause that will only be executed if an if statement is true. This will give you weird results. What you should do is define a variable, say l_oldreadmit, to equal the lag before using it in the if statement.

This will work:

l_oldreadmit = lag(oldreadmit);

if (... whatever you have here ...);
else if 0< gap <= 30 then do;
 index_d=0;
 if l_oldreadmit=1 or oldindex=1  then readmit=1;
     else oth=1;
 oldindex=index_d; 
 oldreadmit=readmit;
 end;

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...