Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
457 views
in Technique[技术] by (71.8m points)

java - Android FileNotFound Exception - Cannot getInputStream from image URL that does not have file format

The title is pretty self explanatory.

the following code...:

    URL imageUrl = new URL(url);
   try {
                HttpURLConnection conn= (HttpURLConnection)imageUrl.openConnection();
                conn.setDoInput(true);
                conn.connect();
                int length = conn.getContentLength();
                InputStream is = conn.getInputStream();
                return BitmapFactory.decodeStream(is);
           } catch (IOException e) {
            e.printStackTrace();
           }

Will fail if the url does not contain the file format. For example, some images hosted by google will display the image yet not have the file format (.png, .jpg, etc) as part of the url.

As a result, the content-type header of the url connection returns "text/html". I believe this is the issue.

I have tried setting a new content-type header, but that doesnt seem to change anything.

anybody know a workaround?

thanks.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

I was running into problems and I remembered googling around and this was my final solution

        try {
            URL url = new URL(imageUrl);
            HttpGet httpRequest = null;

            httpRequest = new HttpGet(url.toURI());

            HttpClient httpclient = new DefaultHttpClient();
            HttpResponse response = (HttpResponse) httpclient.execute(httpRequest);

            HttpEntity entity = response.getEntity();
            BufferedHttpEntity bufHttpEntity = new BufferedHttpEntity(entity);
            InputStream input = bufHttpEntity.getContent();

            Bitmap bitmap = BitmapFactory.decodeStream(input);

            ImageActivity.this.i.setImageBitmap(bitmap);
            ImageActivity.this.i.refreshDrawableState();
            input.close();

        } catch (MalformedURLException e) {
            Log.e("ImageActivity", "bad url", e);
        } catch (Exception e) {
            Log.e("ImageActivity", "io error", e);
        }

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...