templates - C++ partial method specialization

Question

Is there a partial specialization for template class method?

 template <class A, class B>
 class C
 {
  void foo();
 }

it doesn't work to specialize it like this:

template <class A> void C<A, CObject>::foo() {};

Any help?

Answer 1

If you are already have specialized class you could give different implementation of foo in specialized class:

template<typename A, typename B>
class C
{
public:
    void foo() { cout << "default" << endl; };
};

template<typename A>
class C<A, CObject>
{
public:
  void foo() { cout << "CObject" << endl; };
};

---

To specialize member function in Visual C++ 2008 you could make it template too:

template<typename A, typename B>
class C
{
  template<typename T>
  void foo();

  template<>
  void foo<CObject>();
};

The solution above seems to will be available only in future C++ Standard (according to draft n2914 14.6.5.3/2).