Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
243 views
in Technique[技术] by (71.8m points)

c++ - STL less operator and "invalid operator<" error

I have some code that compiles fine in VS 10.0 but after inserting a few items into the Orders map below I receive an "invalid operator <" error in Microsoft debug library. My less operator is simple, just compares the 8 byte string char by char. Anyone have any idea why I would receive this error?

typedef struct MY_orderID_t
{
    char orderID[8];
} MY_orderID_t;

struct std::less<MY_orderID_t>
{ 
   bool operator()(const MY_orderID_t& k1, const MY_orderID_t& k2) const
   {
       for( int i=0; i < 8; i++ )
       {
           if( k1.orderID[i] < k2.orderID[i] )
           return( true );
       }
       return( false );
   }
};

std::map< MY_orderID_t, MY_order_t > Orders[5];
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

I believe that the problem here is that your method of comparing two MY_orderID_t's is not a strict weak order, the type of ordering relation required by the C++ STL. To be a strict weak order, your less-than operator must have the following four properties:

  1. Irreflexivity: x < x is always false.
  2. Antisymmetry: If x < y, then y < x is always false.
  3. Transitivity: If x < y and y < z, then x < z is always true.
  4. Transitivity of Equivalence: If x and y are incomparable and y and z are incomparable, then x and z are incomparable.

Right now, your ordering doesn't obey properties (2) or (3).

*First, (2) is violated by the following:

(0, 4) < (2, 2) 
(2, 2) < (0, 4)

*Second, (3) is violated, because

(0, 1) < (2, 0) < (-1, 1)

// but 

(0, 1) < (-1, 1) // Fail

To fix this, instead of using the comparison you currently have, instead use a lexicographical comparison like this one:

return std::lexicographical_compare(k1.orderID.begin(), k1.orderID.end(),
                                    k2.orderID.begin(), k2.orderID.end());

This comparison is a strict weak ordering and is what's used by all the STL containers by default. Switching to this comparison obeys properties (1) - (4) and should cause everything to work correctly.

Hope this helps!


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...