As you say, you cannot simply redefine a constant in a subclass (it is a constant, after all). The error you get is "Cannot override with a stored property". It does appear to be possible to override a var
, however, when I change the let someVariable
to var someVariable
I get "ambiguous use of 'someVariable'" when I access it in the subclass (note - same thing happens whether I use override
or not).
The simplest solution is to use a getter. This is really a function, so you can happily override it, the backing variable will be managed for you, and if you don't supply a setter ... it will be constant for each class:
class BaseView: UIView {
var someVariable: Int { get { return 1 } }
// do some work with someVariable
}
class ExtendedView: BaseView {
override var someVariable: Int { get { return 2 } }
}
let a = BaseView()
a.someVariable // 1
let b = ExtendedView()
b.someVariable // 2
As commentator @user3633673 points out, if you only have a getter (and not a setter), you can drop the get
, but I left it in for clarity of the principle. Here's the same without it...
class BaseView: UIView {
var someVariable: Int { return 1 }
// do some work with someVariable
}
class ExtendedView: BaseView {
override var someVariable: Int { return 2 }
}
let a = BaseView()
a.someVariable // 1
let b = ExtendedView()
b.someVariable // 2
... and, of course, in Swift 5, you can drop the return
:
class BaseView: UIView {
var someVariable: Int { 1 }
}
class ExtendedView: BaseView {
override var someVariable: Int { 2 }
}
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