oop - Any way to _not_ call superclass constructor in Java?

Question

If I have a class:

class A {
   public A() { }
}

and another

class B extends A {
   public B() { }
}

is there any way to get B.B() not to call A.A()?

Answer 1

There is absolutely no way to do this in Java; it would break the language specification.

JLS 12 Execution / 12.5 Creation of New Class Instances

Just before a reference to the newly created object is returned as the result, the indicated constructor is processed to initialize the new object using the following procedure:

1. Assign the arguments for the constructor [...]
2. If this constructor begins with an explicit constructor invocation of another constructor in the same class (using this), then [...]
3. This constructor does not begin with an explicit constructor invocation of another constructor in the same class (using this). If this constructor is for a class other than Object, then this constructor will begin with an explicit or implicit invocation of a superclass constructor (using super).
4. Execute the instance initializers and instance variable initializers for this class [...]
5. Execute the rest of the body of this constructor [...]