So I have a script that has date arguments for different functions and I want it to loop through 01-01-2012
to 06-09-2012
not including weekends. Im trying to figure out a way I can use time delta because my script outputs files with the date used in the name of the file for example:
items = (functions.getItems(item,date)
print items
test = sum(abs(l[-1]) for l in items)
total = open('total' +str(datetime.today- datetime.timedelta(1)),'a')
I want timedelta(1) to cycle through each date so that the output file would have the format of total2012-01-01
for the first day and cycle through until it created the file total2012-06-09
. Also the date argument for items has the format of MM-DD-YYYY
I thought that I could do this:
sd = 01-01-2012
ed = 06-09-2012
delta = datetime.timedelta(days=1)
diff = 0
while sd != ed
# do functions
# (have output files (datetime.today - datetime.delta(diff))
diff +=1
sd+=delta
So essentially I'm just trying to figure out how can I loop through having the function start with 01-01-2012
and ending with 06-10-2012
excluding weekends. I'm having trouble figuring out how to exclude weekends and how to get it to loop in the proper order
Thanks
See Question&Answers more detail:
os 与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…