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in Technique[技术] by (71.8m points)

如何用正则表达式实现字符串反转

想要实现的效果:
aaaaabbbbbcccc -> ccccbbbbbaaaaa

希望可以通过正则表达式+replace的方式实现


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by (71.8m points)
var result = 'aaaaabbbbbcccc'.replace(/./g, (char, offset, str) => {
  return str[str.length - offset - 1];
})

console.log(result)

背景是啥,非要这么实现。换个方式不行?

[...'aaaaabbbbbcccc'].reverse().join('')

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