Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
297 views
in Technique[技术] by (71.8m points)

python - Pandas Lambda Function with Nan Support

I am trying to write a lambda function in Pandas that checks to see if Col1 is a Nan and if so, uses another column's data. I have having trouble getting code (below) to compile/execute correctly.

import pandas as pd
import numpy as np
df=pd.DataFrame({ 'Col1' : [1,2,3,np.NaN], 'Col2': [7, 8, 9, 10]})  
df2=df.apply(lambda x: x['Col2'] if x['Col1'].isnull() else x['Col1'], axis=1)

Does anyone have any good idea on how to write a solution like this with a lambda function or have I exceeded the abilities of lambda? If not, do you have another solution? Thanks.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

You need pandas.isnull for check if scalar is NaN:

df = pd.DataFrame({ 'Col1' : [1,2,3,np.NaN],
                 'Col2' : [8,9,7,10]})  

df2 = df.apply(lambda x: x['Col2'] if pd.isnull(x['Col1']) else x['Col1'], axis=1)

print (df)
   Col1  Col2
0   1.0     8
1   2.0     9
2   3.0     7
3   NaN    10

print (df2)
0     1.0
1     2.0
2     3.0
3    10.0
dtype: float64

But better is use Series.combine_first:

df['Col1'] = df['Col1'].combine_first(df['Col2'])

print (df)
   Col1  Col2
0   1.0     8
1   2.0     9
2   3.0     7
3  10.0    10

Another solution with Series.update:

df['Col1'].update(df['Col2'])
print (df)
   Col1  Col2
0   8.0     8
1   9.0     9
2   7.0     7
3  10.0    10

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...