Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
281 views
in Technique[技术] by (71.8m points)

python - Pandas DataFrame: Simple assignment - the floor of the difference of two column values to another column value, loop does not work

How would you perform the following in Pandas?

import math
for index, row in data.iterrows():
  if row["year"] == 0:
    row["year"] = math.floor((row["death"] - row["birth"])/2)

This loop does not work but what i am trying to do is to assign the floor of the difference divided by 2 of the death and birth columns to the column year if the column year has the value 0. I know you should avoid looping in Pandas and this probably has a simple solution but i can not figure it out right now.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Reply

0 votes
by (71.8m points)

Use numpy.where:

import numpy as np

df['newcol'] = np.where(df['year'] == 0, math.floor((df['death'] - df['birth'])/2), df['year'])

This essentially is:

np.where(condition, if True then, if False then)

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
OGeek|极客中国-欢迎来到极客的世界,一个免费开放的程序员编程交流平台!开放,进步,分享!让技术改变生活,让极客改变未来! Welcome to OGeek Q&A Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...